Solution:

445

2=(1+1)1
6=(2+1)2
21=(6+1)3
88=(21+1)4

So 445=(88+1)5

Solution:

N for November

M: March
A: April
M: May ....and so on ...

Solution:

794

The nth term in the series is given by the sum of x^n for x in the range 1 to 3, i.e. 1^n + 2^n + 3^n.

Thus the first term is 1^1 + 2^1 + 3^1 = 1 + 2 + 3 = 6,
the second term is 1^2 + 2^2 + 3^2 = 1 + 4 + 9 = 14,
and so on.

The sixth term is then 1^6 + 2^6 + 3^6 = 1 + 64 + 729 = 794.

Solution:

61

Reversed digits of squares of number in descending order.

Solution:

129.

These are the first 10 prime numbers (2, 3, 5...) prefixed with a 1

Solution:

N for Nine

Solution:

6526884.

To get from 4 to 12, you use the following formula. 12 = (4 squared)/2 + 4.
Continue on with (X^2)/2 + X.

Solution:

The missing number that fit in ? is 6.

The number in the middle of each triple is the same as the digits of either end's number when added together. 3+7=10=8+2 and so on.

Solution:

143547

Solution:

Each word rhymes with its numeric position in the list. (e.g. 'gun' rhymes with 'one'
etc.)