Solution:

18

Explanation:
Let us suppose that there were (3 * G) garlic bread sticks originally.

On dividing equally, the number of bread sticks with each of the friend = G

Each one of them ate four. The remaining sticks with each one of them = (G - 4)

Now, the total number of breadsticks left = 3 * (G - 4)
This number is equal to the breadsticks each one of them had after division.

=> 3 * (G - 4) = G
(3 * G) - 12 = G
2 * G = 12
G = 6.

Therefore, the number of breadsticks originally = 3 * G = 3 * 6 = 18.

Solution:

You will address him as your father or uncle. (Husband of your mother).

Solution:

Muz is the required code word.

In the statements (1), (2) and (3), common coded word is 'Stew' and common normal word is 'are'. Therefore, 'Stew' = 'are'.
k
In the statements (1) and (4), common coded word (except 'are') is 'Choi' and common normal word is 'Spirits'. Therefore, 'Choi' = 'Spirits'.

Likewise, in the statements (2), (3) and (4), common coded word is 'Fru' and common normal word is 'Sinister'. So, 'Fru' = 'Sinister'.

Hence, 'Choi', 'Stew', 'Fru' means 'Spirits', 'are', 'Sinister' respectively. Thus, in statement (4), the remaining word i.e., 'Muz' = 'the'.

Solution:

The required word is Buffalo.

Buffalo is a noun that refers to an animal. However, it is also a verb that means 'to bully'. Let us see how it can be used.

Sentence: Buffalo.
Meaning: Go and bully someone.

Sentence: Buffalo buffalo.
Meaning: Animals bully.

Sentence: Buffalo buffalo buffalo.
Meaning: Animals bully other animals.

Sentence: Buffalo buffalo buffalo buffalo.
Meaning: Animals that are bullied by other animals, in turn, bully other animals.

Solution:

119

Explanation:
Let the minimum number of chocolates = C
When divided by 2, remainder = 1
When divided by 3, remainder = 2
When divided by 4, remainder = 3
When divided by 5, remainder = 4
When divided by 6, remainder = 5
When divided by 7, remainder = 0

Therefore, C is divisible by 7.

Whenever C is divided by any number less than 7, the remainder is 1 less than the divisor.
This implies that, C + 1 is the LCM of 2, 3, 4, 5 and 6.

Now LCM of 2, 3, 4, 5 and 6 = 60
But 60 - 1 = 59 is not divisible by 7

60 * 2 = 120
120 - 1 = 119 which is divisible by 7

Therefore, C + 1 = 120 or C = 119

Number of minimum number of chocolates in the box = 119

Solution:

The solution is given in the attached image.

Solution:

Assuming that John has A number of apples and Jacobs has B number of apples.

As per the question,
A + 1 = B - 1
=> B - A = 2 ------ (p)

Also, A - 1 = (B + 1) / 2
=> 2A - B = 3 ------ (q)

Solving (p) and (q)
A = 5 and B = 7

Therefore, A has 5 chocolates and B has 7 chocolates right now.

Solution:

125

Explanation:
The trick that has been used here is that all the corner digits have been reversed and then added. The sum is than placed in the center.

In the first square:
13 + 32 + 11 + 34 = 90

In the second square:
21 + 19 + 27 + 16 = 83

In the third square:
33 + 33 + 22 + 26 = 125

Thus the missing number is 125

Solution:

Parent of B is Alex.
Parent of Faina is Enrique.
Parent of Duke is Christy.
Enrique is Alex's brother and Christy is Alex's sister.
Thus, Faina, B and Duke are cousins.

Solution:

The number will be 30.

In the first circle
(5 + 4) * 2 = 18

In the third circle
2. (12 + 8) * 3 = 60

In the fourth circle
3. (3 + 9) * 4 = 48

Similarly In the fifth circle
4. (4 + 2) * 5 = 30