Solution:

Daniel Agger, Steven Gerrard, Nuri Sahin, and Raheem Sterling stated a contradiction statement, so only one of them can said the truth.
We don't know yet where Luis Suarez stands, it's still possible that he has black or white color.
Thus, the maximum possibility of white dots are 2, that is Luis Suarez and 1 of Daniel Agger Steven Gerrard Nuri Sahin, and Raheem Sterling.
Daniel Agger and Raheem Sterling obviously told the lie, as they said there are 3 and 4 person has white dot, which leave us Steven Gerrard and Nuri Sahin .
Assuming Steven Gerrard is white, then he must be telling the truth that he saw 4 black dots, which makes Nuri Sahin a liar. This is an impossible situation, since Nuri Sahin saw 3 black and 1 white (Nuri Sahin has to be a liar, so there must be more than 1 white, meaning it's impossible Steven Gerrard saw 4 blacks).
The only possibility is Nuri Sahin told the truth.
So, Daniel Agger Steven Gerrard Raheem Sterling have black dots, while Nuri Sahin and Luis Suarez have white dots.

Solution:

100. Looks hard? Don't worry, just work it backwards and you'll find it very easy.

Solution:

The required number is 236 and the sum is 11.

It is given that the first two digits of the required number are prime numbers i.e. 2, 3, 5 or 7. Note that 1 is neither prime nor composite. Also, the third digit is the multiplication of the first two digits. Thus, first two digits must be either 2 or 3 i.e.
22, 23, 32 or 33 which means that there are four possible numbers - 224, 236,326 and 339.
Now, it is also given that - the difference between it's reverse and itself is 396.
Only 236 satisfies this condition. Hence, the sum of the three digits is 11.

Solution:

5 4
x 3
----
162

Solution:

7 (SEVEN-S=EVEN)

Solution:

18 x 12 ÷ 4 + 5 = 59

Solution:

Breakfast

Solution:

47 + 53 + 59 + 61 = 220

Solution:

A Stamp

Solution:

In one hour,

Soln 1:
the large inlet tube fills 1 / 3 of the tank;
the small inlet tube fills 1 / 6 of the tank;
the outlet tube empties 1 / 9 of the tank; and therefore
all three tubes together fill [ (1 / 3) + (1 / 6) − (1 / 9) ] of the tank.

Fraction of the tank that will be filled in 0.64 hours =
0.64 [ (1 / 3) + (1 / 6) − (1 / 9) ] = 0.25.


Soln 2:
Let V be the total volume of the tank. From equation (1),

Flow Rate (large inlet tube) = V / 3
Flow Rate (small inlet tube) = V / 6
Flow Rate (outlet tube) = V / 9.

Substituting in equation (2),

Rate of Accumulation in tank = (V / 3) + (V / 6) − (V / 9).

Using the above result in equation (1),

Time required to fill the complete tank = V / [ (V / 3) + (V / 6) − (V / 9) ].

Note that V cancels out on simplifying the above expression.

Fraction of the tank that will be filled in 0.64 hours =

0.64 [ (1 / 3) + (1 / 6) − (1 / 9) ] = 0.25.