Solution:

104

Solution:

2024

Seven occurrence
24-01-24
12-02-24
08-03-24
06-04-24
04-06-24
03-08-24
02-12-24

Solution:

125874 => 251748

251748 is twice the 125874 and have same digits 1,2,4,5,7 & 8

Solution:

186

Explanation :
21+11*1 => 32
32+11*2 => 54
54+11*3 => 87
87+11*4 => 131
131+11*5 => 186

Solution:

Rendezvous

Solution:

Perhaps surprisingly, the apples now weigh 50 kilograms. The sack of apples originally weighed 100 kilograms, and 1 percent of its weight, or 1 pound, was non-water. If that 1 pound now makes up 2 percent of the total weight, then the total weight must be 50 kilograms.

Solution:

From left to right
#1 Mr. Reed Richard – Blue Marbles
#2 Ms. Sue Storm – Red Marbles
#3 Mr. Johnny Storm – White Marbles
#4 Mr. Ben Grimm – Green Marbles.

Let us label the houses from left to right as #1, #2, #3, #4. Now let us split the hints in different category.
a) Mr. Reed Richard’s house is to the left of the green marbles one
b) The third one is made of white marbles
c) Ms. Sue Storm owns a red marbles house
d) Mr. Johnny Storm does not live on either ends
e) Mr. Johnny Storm lives right of the blue marbles house
f) Mr. Ben Grimm lives in the fourth house
g) The first house is not made up of red marbles

By seeking all the (g) and (b), we are sure that the #1 is not made up of red marbles and nor is the #3. Now with (f) we know that Mr. Ben Grimm lives in #4 made up of green marbles and keeping in mind (c) #2 must be made of Red Marbles and Ms. Sue Storm lives there. Now moving to the hint (d) Mr. Johnny Storm must be living in #3 and adding up with hint (b), it must be made from white marbles. Now by hint (a) #4 must be made up of green marbles (or Mr. Reed Richard’s house can’t be on its left). Also by (f) Mr. Ben Grimm lives there. All of it leaves Mr. Reed Richards living in #1 with blue marbles construction.

Solution:

Arc + tick + circle.
= Artic Circle

Solution:

No one understands

Solution:

987,654

Let us assume with a smaller number and then increase the number by extrapolating. If there are two citizens, the number of hairs on their heads will be zero and one. Therefore for ‘n’ number of citizens, the hair distribution will range from 0 to (n-1).

If you take up a case of a number greater than 987,654 let’s say 987,655; and consider the fact that none of the citizens have 987,654 hairs and they must be having different number of hairs, one must be having more than 987,654 hairs which is bluntly violating the fact of the town that there are more citizens than the hairs on any individual.