Solution:

Option C

In shape A, the outer figure possesses 4 sides, while the inner figure contains 3 sides.
In shape B, the outer figure exhibits 5 sides, while the inner figure showcases 4 sides.
In shape C, both the outer figure and the inner figure encompass 4 sides.
In shape D, the outer figure displays 7 sides, and the inner figure encompasses 6 sides.

Apart from Shape C, in all the other shapes, the number of sides on the outer figure exceeds that of the inner figure by just one.

As a result, the image that deviates from this pattern is Shape C.

Solution:

It can surely be true because it is not mentioned that it was raining.

Solution:

C7 => B8
Exchange pawn for a knight

Check-Mate

GameOver

Solution:

Move the coins as given in the figure and you will get the required result.

Solution:

20
Just count the nines in the numbers: 6, 16, 26, 36, 46, 56, 76, 86, 96, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69.
Note: 66 contains TWO nines

Solution:

Set the first switches on for abt 10min, and then switch on the second switch and then enter the room.
Three cases are possible
1.Bulb is on => second switch is the ans
2.Bulb is off and on touching bulb , you will find bulb to be warm
=>1st switch is the ans.
3.Bulb is off and on touching second bulb , you will find bulb to be normal(not warm)
=>3rd bulb is the ans.

Solution:

They are matched as shown in the picture below.

Solution:

White should move the rook from
A1 to D1 and hence complete the castling move.

Solution:

Lucky days are here again.

Explanation:
Lucky + Day + s + R + H + Ear + Again (Flower represent lucky symbol)

Solution:

73

Explanation:
It's a very famous puzzle known as "Josephus Problem Puzzle". It can be solved in various ways but the trick to solve this problem is illustrated below.

Binay number of 100 is: 1100100
complement pf 100 is 0011011, whose decimal equivalent is 27.
The desired answer will be 100 - 27 = 73

Solution:

Sam : 2
Dean : 5
Castiel : 7

Age diff
7 - 2 = '5' is prime
7 - 5 = '2' is prime
5 - 2 = '3' is prime