Solution:

84years old


The first equation (365g = 52s) can be approximated by
7g = s.

As before, the other two equations are
12g = m
g + s + m = 140.

The above system of 3 equations in 3 unknowns (g, s and m) can be simply solved as follows.
g + 7g + 12g = 140 or 20g = 140.
m = 12g = 12 × 140 / 20 = 84.

So, Grandpa is 84 years old.

Solution:

No time at all it is already built

Solution:

Let the sum of nine member (total) =x
and the age of old one=z
so its average 4 yrs before=(x+z)/10.
after 4 yrs let z be replaced by y.
so now avg=(x+4*10+y)/10

now (x+z)/10=(x+40+y)/10
so after solving it found
z=y+40.
so old person is 40yrs older than young one.

Solution:

The complete addition looks as follows:

  167161 +
  664711 +
  162166 +
  164611
-------------
1158649

Solution:

20 units, 12 units & 15 units

As hard as it may sound, we have to just apply some basic algebraic equations to solve it.
Let the three sides be X, Y and Z. Now, the area of different surfaces is given:
X * Y = 240
Z * Z = 300
Y * Z = 180

Multiplying the obtained equations:
(X*Y) (X*Z) (Y*Z) = 240 * 300 * 180
X^2 * Y ^2 * Z^2 = 12960000
(X*Y*Z)^2 = 12960000
X*Y*Z = 3600

Now we know that X*Y = 240

Thus Z = 3600/240 = 15.

If we put the given values in the same manner, we get the three sides:
X = 20 units
Y = 12 units
Z = 15 units

Solution:

B, D and E are absolutely identical to the green figure.

Solution:

35

Solution:

It is not as tough as it seems. The strategy is quite simple. You just have to pick up a card out of first three whenever you find a 9 or higher number.

Let us offer you a strong valid reason for the strategy. The probability that the four card kept below are below the number nine is 32*31*30*29 / 52*51*50*49 = 0.133
Thus in such case, you will lose $2 to $9 with equal probability = 0.133/8 = 0.0166

Let us now calculate the probability that one of the four cards is nine or even higher.
1 – 0.133 = 0.867
Now you will surely stop at the first sight of 9 or any value above 9 as per the strategy. Thus you have a chance of winning -1, 0, 1, 2, 3 with an equal probability = 0.867/5 = 0.173

In such case you stand a chance of winning overall amount of 0.14 every game you play.

Let us consider the other strategies. If you want to stop at the sight of 10 or above 10, the expected amount you will win per game will be 0.09 which is way below the present strategy. If you want to stop at above ten only, you will have an expected winning in negative.

Solution:

I am a windmill.

Solution:

I am Voice