Solution:

2024

Seven occurrence
24-01-24
12-02-24
08-03-24
06-04-24
04-06-24
03-08-24
02-12-24

Solution:

1)The first bit is easy, as the first letter of each plate spells WHODUNNIT IX(A challenge to our Detective.)
2)The second bit is a little trickier, but I gave you the solution.If you read the last three letters in each plate from the bottom up and right to left you get ADVANCE EACH LETTER BY THE NUMBER SHOWN, so advance W by 5 to get B, H by 13 to get U and so on until you spell BUTLER DID IT.

Solution:

* The first surgeon operates with the first glove (glove A) inside the
second glove (glove B).

* The second surgeon operates using just glove B.

* The third surgeon operates using glove A, turned inside out, inside glove B.

Solution:

10 o'clock + 4 hours = 2 o'clock.

Solution:

Newspaper delivery man was the murderer because of absence of Wednesday and Thursday missing newspaper.
This indicates he already know that there is no one to read it.

Solution:

As per the puzzle given above The fewest number of aircraft is 3! Imagine 3 aircraft (A, B and C). A is going to fly round the world. All three aircraft start at the same time in the same direction. After 1/6 of the circumference, B passes 1/3 of its fuel to C and returns home, where it is refueled and starts immediately again to follow A and C.

C continues to fly alongside A until they are 1/4 of the distance around the world. At this point C completely fills the tank of A which is now able to fly to a point 3/4 of the way around the world. C has now only 1/3 of its full fuel capacity left, not enough to get back to the home base. But the first 'auxiliary' aircraft reaches it in time in order to refuel it, and both 'auxiliary' aircraft are the able to return safely to the home base.

Now in the same manner as before both B and C fully refueled fly towards A. Again B refuels C and returns home to be refueled. C reaches A at the point where it has flown 3/4 around the world. All 3 aircraft can safely return to the home base, if the refueled process is applied analogously as for the first phase of the flight.

Solution:

Mark Benson '?' = question MARK, so the note on the door reads 'Question Mark Crimson broke your window.'

Solution:

==Solution 1==
Pamela is Michael's daughter. This is because Michael is Shelly's son. Also he is married to one of the Joseph's daughters. Joseph's other daughter is married to Harry and Danny is their son.

==Solution 2==
Michael and Harry are brothers. Shelly is their mother. In this case, 'Harry's wife's sister's husband's mother's son' refers to Harry himself. Thus, Danny is Michale's son and Pamela is Harry's daughter which means that Pamela is Michael's niece.

Solution:

First climb the first rope and carry the end of the second one with you. Now cut the first rope and flush with the ceiling, then swing down on the second. This time, climb up the second and cut that flush with the ceiling as well but only part way till it can withstand your weight. Now slowly climb down till you're just short of the bottom. Now tie a tiny loop at this portion and climb up some two feet. Then secure the loop about your feet and jump to the ground. With a three feet fall, you won't be hurt but the force will snap off the rope at top and you will have the whole rope with you.

Solution:

The best way to analyze the situation would be forcing a win for white when the black player plays anywhere but a corner square. Refer to the given figure for the current positions. Now, if black plays 7 to block the white player from having three in a row, white will move 5 to 6 and will win. But since you get to place only three markers, black can place the marker at 6 and white won't be able to add one more at 7 to win. And moving the 9 marker to 7 will take two steps.

But white can still get to square 7 before black is able to block him or form a three in a row. In this manner, no matter what black does, the white player can always win the game if he begins from the center square.