Solution:

Absolute(Maths Symbol) + lee + Not(0)
= Absolutely Not

Solution:

3 minute and 25 (5/7) seconds.

Explanation:
What you may possibly do is add 3 and 4 minutes and take up the sum of 7 as an average to proceed further. However that is totally wrong as the wind has only supported Josh for 3 minutes while it has acted adversely for 4 minutes.

Thus first we must calculate the distance if he would have travelled for equal time along with wind i.e. 4 minutes. Clearly he would have travelled a mile and 1/3 of a mile in 4 minutes. Now adding the total distance in eight minutes i.e. 2 and 1/3 mile we can get his actual speed and time.

Thus the actual time for a single mile will be 3 minute and 25 (5/7) seconds.

Solution:

For(4) + a + change(delta/change symbol)
= For a change

Solution:

Route(Root symbol) + 66
= Route66

Solution:

This problem can be solved with similar triangles property.
The White triangle is similar to the Red one
Now Ratio of sides is 2:3 (as ratio of areas = ratio of based if the height is same)
Seeking that, White triangle = 9/4 * Yellow triangle = 9/2
Following all the above, the Green region = 5.5 units

Solution:

12

Explanation:
The amount won and lost by both is equal.
Thus 2x = 3(20-x) --- x in the number of times heads came
X = 12

Solution:

On multiplying all the 6 pairs we get (a*b*c*d)^3.
Assuming the missing product is a*b, then amid the 5 given products we see (a*c)*(b*d)=(a*d)*(b*c)
If we look at the numbers clearly 5 is out of the equation because there is nothing to balance it so the only remaining match is 2*6=3*4, so a*b*c*d=2*6=12.
So the product of all 6 pairs should be 12^3, the product of the given 5 is 720, so the missing one is 12/5=2.4

Solution:

88 + 88/88

Solution:

10 miles

Solution:

Man1 is carrying 5 bags and the Man2 is carrying 7 bags.

Let's assume that the Man1 was carrying M1 bags and the Man2 was carrying M2 bags.
M2 + 1 = 2 * (X-1)
M2 + 1 = 2M1 - 2
M2 = 2M1 - 3

Also,
M2 - 1 = M1 + 1
M2 = M1 + 2

=>
2M1 - 3 = M1 + 2
M1 = 5

=>
M2 = 7