Solution:

930

Explanation:
New number = Last number * multiplication factor (increased by 0.5 every time) + sum factor (increased by 5 every time)
10
10 * 0.5 + 5 => 10
10 * 1.0 + 10 => 20
20 * 1.5 + 15 => 45
45 * 2.0 + 20 => 110
110 * 2.5 + 25 => 300
300 * 3.0 + 30 => 930 , desired answer

Solution:

454585

Explanation:
Number is formed as (numA*numB)(numB*numC)(numC*numA)
Following the formular, 1st row will be like
5+3+2 => 5*3 3*2 2*5 => 151022
Simillarly
(9*5)(9*5)(9*5+9*5-5) => 454585

Solution:

11.3135 + 9.3115+ 9.375

Solution:

168
12 14
6 2 7
3 2 1 7

Explanation:
If we multiply two numbers below, we will get the number above it.
like. 3*2 of the last row =>6 of the third row.

Solution:

27

Explanation:
16/2 = 9
8*3 = 24
24/2 = 12
12*3 = 36
36/2 = 18
18*3 = 54
54/2 = 27
27*3 = 81

Solution:

1262

Sequence is based on formula:
Next = (1st Number)^2 - (2nd number)

7 12 37 ? 9142

7^2 - 12 = 37
12^2 - 37 = 107
37^2 - 107 = 1262 (Answer)
102^2 - 1262 = 9142

Solution:

151 (131+20)

Explanation:
1st 7 prime numbers post 100 are
101 , 103 , 107 , 109 , 113 , 127 , 131
...Adding 20 to numbers
121 , 123 , 127 , 129 , 133 , 147 , 151

Solution:

The next number is 392.

The first number = (Square of 1 + Cube of 1)
The second number = (Square of 2 + Cube of 2)
The third number = (Square of 3 + Cube of 3)
The fourth number = (Square of 4 + Cube of 4)
The fifth number = (Square of 5 + Cube of 5)
The sixth number = (Square of 6 + Cube of 6)
Therefore, the seventh number will be
Square of 7 + Cube of 7 = 392.

Solution:

89 (ASCII CODE OF Y)

Q W E R T Y
81 87 69 82 84 ?

Solution:

The series are prime numbers with one added to it.
The original prime numbers are as follows.
101, 103, 107, 109, 113, 127