Solution:

5

23-2=21
21+3=24
24-5=19
19+7=26
26-11=15
15+13=28
28-17=11
11+19=30
30-23=7
7+29=36
36-31=5


(2,3,5,7,11,13,17,19,23,29,31,37,41,43... are Prime Numbers)

Solution:

24

write the numbers in ascending order in words as
onE (Position of 'E' in alphabet is 5)
twO (Position of 'O' in alphabet is 15)
threE (Position of 'E' in alphabet is 5)
fouR (Position of 'R' in alphabet is 18)
and so one

Solution:

445

2=(1+1)1
6=(2+1)2
21=(6+1)3
88=(21+1)4

So 445=(88+1)5

Solution:

794

The nth term in the series is given by the sum of x^n for x in the range 1 to 3, i.e. 1^n + 2^n + 3^n.

Thus the first term is 1^1 + 2^1 + 3^1 = 1 + 2 + 3 = 6,
the second term is 1^2 + 2^2 + 3^2 = 1 + 4 + 9 = 14,
and so on.

The sixth term is then 1^6 + 2^6 + 3^6 = 1 + 64 + 729 = 794.

Solution:

6526884.

To get from 4 to 12, you use the following formula. 12 = (4 squared)/2 + 4.
Continue on with (X^2)/2 + X.

Solution:

B.

In every line and column, there are bicycles where 2 of them are facing left, and 1 is facing right, 2 with 2 pedals, and 1 with 12 with a steering wheel and 1 without.

Solution:

RS

Explanation:
The list is formed by using last two letter of planet's names in the order from Neptune To Mercury

NEPTU-NE
URAN-US
SATU-RN
JUPIT-ER
MA-RS
EAR-TH
VEN-US
MERCU-RY

Solution:

17

Explanation:
1
3 = one (3 letters)
8 = three (5 letters) + one (3 letters)
13 = Eight (5 letters) + three (5 letters) + one (3 letters)
21 = Thirteen (8 letters) + Eight (5 letters) + three (5 letters) + one (3 letters)
17 = twentyOne (9 letters) + Thirteen(8 letters)

Solution:

5 of clubs.

Explanation:
The 5th number is equal to the sum of first four number (recursively until its value <=13). The suit will be same as of biggest card.
eg Row1:
5 + 7 + 3 + 11 = 26 = 8
Since Maximum value is Jack of hearts, therefore, we will get 8 of hearts

Similarly for the last row
12+13+2+5 = 32 = 5
Since Maximum value is King of a club, therefore, we will get 5 of a club.

Solution:

Z

Explanation:
The numeric value of the first two alphabets adds up to the numeric value of the last alphabet.