Solution:

Ruskin Stole Chihuahua
Sam stole Hyena
Terry Stole Deer

Explanation:
Let us consider the first two statements again; they are conflicting. However both can be true together. Also both of them cannot be incorrect which means that Terry stole Chihuahua and his statement will be true. But it has been already inferred that the one who stole Chihuahua was telling a lie thus it can’t be possible.

Focus on the given facts again. Terry might have stolen a hyena or a deer. Let us say that he stole hyena. In such an event the statement of Terry will be untruthful. But we know that the person who stole hyena told the truth, thus it is controverting our hypothesis and so cannot be true.

Considering everything, now we can be sure of the fact that Terry stole the deer.

It means that the declaration by Ruskin is totally false and the declaration by Sam is true which shows that the Chihuahua and hyena are stolen by these two. Also we know that the one who stole hyena is correct and the one stealing Chihuahua is a falsifier. Thus we now know that Ruskin stole Chihuahua and Sam stole hyena.

Solution:

B

sideways clockwise 1/4 turn

Solution:

Answer
Kid4 and Kid6

Solution: According to given information, sitting arrangement of six people is -

Kid4 Kid5 Kid1 Kid3 Kid2 Kid6
or
Kid6 Kid1 Kid3 Kid2 Kid5 Kid4
or
Kid4 Kid5 Kid2 Kid3 Kid1 Kid6
or
Kid6 Kid2 Kid3 Kid1 Kid5 Kid4

So, in all the situations, Kid6 and Kid4 are at corners of the row.

Solution:

Step1 -> Start running both the hourglasses.
Step2 -> When 4 hours hourglass runs out, turn it over.
Step3 -> When 7 hours hourglass runs out, turn it over.
Step4 -> Again when 4 hours hourglass runs out, turn 7 minute hourglass over (it was running for exactly one minute.)
final step -> 8 minute already passed and allow one minute of 7 hour glass to get over. ==>9 minute

Solution:

C

VIII has taken place of VII.

Solution:

Man1 is carrying 5 bags and the Man2 is carrying 7 bags.

Let's assume that the Man1 was carrying M1 bags and the Man2 was carrying M2 bags.
M2 + 1 = 2 * (X-1)
M2 + 1 = 2M1 - 2
M2 = 2M1 - 3

Also,
M2 - 1 = M1 + 1
M2 = M1 + 2

=>
2M1 - 3 = M1 + 2
M1 = 5

=>
M2 = 7

Solution:

zero

6 without head => 0
9 without tail => 0
8 in two halves => 0 & 0

Solution:

The first one cannot be aishwarya, because that would make the first one a liar. The second one cannot be aishwarya for the same reason. So, the third sister must be aishwarya. This means the middle one is kareena and the only one left is katrina.

Solution:

Megan (9:00AM) - Keira (11:00AM) - Penelope (8:00PM) - Charlize (10:00PM)

From the given data, it is clear that at least one female visited me in the morning and at least one female visited me in the evening. Also, from (4), Penelope did not visit me first. It means that Penelope visited me at 8:00 PM. From (3), Megan must have visited me at 9:00 AM. Also, either Charlize or Keira or both visited me in the morning. But from (2), only Keira must have visited me in the morning at 11:00 AM and hence, Charlize visited me at 10:00 PM.

Solution:

Edward is Bella's date.

As no two of them have the same number of preferred traits - from (1), exactly one of them has none of the preferred traits and exactly one of them has all the preferred traits.

From (4) and (5), there are only two possibilities:
* Lautner & Edward both are tall and Jacob & Welch both are fair.
* Lautner & Edward both are short and Jacob & Welch both are dark.

But from (2), second possibility is impossible. So the first one is the correct possibility i.e. Lautner & Edward both are tall and Jacob & Welch both are fair.

Then from (3), Jacob is short and handsome.

Also, from (1) and (2), Lautner is tall and fair. Also, Welch is the person without any preferred traits. Edward is Dark. Lautner and Edward are handsome. Thus, following are the individual preferred traits:

Edward - Tall, Dark and Handsome
Lautner - Tall and Handsome
Jacob - Handsome
Welch - None :-(

Hence, Edward is Bella's date.