Solution:

1) 8/(3-(8/3))
= 8/(1/3)
= 24

2)((8 x 3!)/3)+8
= ((8 × 3 × 2 × 1)/3)+8
= (48/3)+8
= (16)+8
= 24

3)(3!/)*8

4)(8-3)!/(8-3)
( × )!
( + )!
?(8×8×3×3)
8+(8×(3!/3))
((?(8+8) × (3/3))!
?(8+8) × (3+3)
(log base(3!/3) of 8) × 8
((log base(3!/3) of (8+8))!

Solution:

We can calculate out how many days there will be for the 13th on each month if we count from the beginning of the year (January 1). Then we divide total days by 7 to get the remainders. We also need to consider the leap year. Through the whole year we had all kinds of remainders, from 0 to 6. The minimum of occurence for all the unique remainders was 1. It means that we have at least one Friday on 13th. In a regular year, the best chance you can get 3 Fridays on 13th, which are in February, March and December because the remainders of these 3 months are 2. In a leap year, the best chance you also can get 3 Fridays on 13th, which are in January, April and July because the remainders of these 3 months are 6.

Solution:

29

Jacob standing on the middle rung.
He goes up 6 rungs so he is now at M+6 and when he goes down 10 rungs so he is at M-4.
Jacob goes up 18 rungs so he is now at M+14 = T

14 rungs from the top, 14 rungs from the bottom, and the middle rung. 14+14+1=29

Solution:

3

The total sum is always 17.

Solution:

9

4x + 21 = 57
4x = 36
x = 9

Solution:

30

Explanation:
As you can see the lower number rows are always bigger than upper row ones with the difference going up by 3 with every step

34 - 32 = 2
32 - 27 = 5 (difference going up by 3 from last difference)
56 - 48 = 8 (difference going up by 3 from last difference)
? - 19 = 11 (difference going up by 3 from last difference)
so ? = 30

Solution:

180

Solution:

2

36 - 6 / (1/6) + 2
= 36 - 6 * 6 + 2
= 36 - 36 + 2
= 2

Solution:

4100.

In a survey conducted 1/5 has written answer ar 5000.

1000 + 40 = 1040
1040 + 1000 = 2040
2040 + 30 = 2070
2070 + 1000 = 3070
3070 + 20 = 3090
3090 + 1000 = 4090
4090 + 10 = 4100 ... The answer

Solution:

58