Solution:

Form an equilateral triangle. Now place three cones on the vertices. Now place one cone on each of the three edges, at their middle point. The last cone must be kept at the centroid of the triangle.

In this manner, you will get 3 rows corner to corner and 3 rows via the centroid and each will have 3 cones only.

Solution:

He will hang clock number 315 at 7:30pm. The person has been hanging the clock number which corresponds with the angle between the hour hand and the minute hand of the clock at that time.

Solution:

The answer is simple. The trains will be at same distance from Point P when they meet speaking on approximation. However, the train A will be closer to the point P by its own length if we are not taking meeting of train as perfectly overlapping.

Solution:

When fifteen minutes have passed, the hour hand has already moved exactly one fourth of an hour. Thus the angle between the hour hand and minute hand will be of 7.5 degrees.

Solution:

I had 10 candies in the beginning.

Explanation:
Let us take and solve this problem in the reverse direction.

At the end, I was left with 1 candy. Let me take the extra one candy back from my younger son. Now since I gave him half of what I had, we must be having the same number of candies. I have 2, which means he also have 2. This implies that I was left with 4 candies after I gave some to the elder son.

Let me take back the extra candy from my elder son now. Now I have 5 candies. Since I gave him half of what I had, he must be having 5 candies as well. Thus, I had 10 candies in the beginning.

Solution:

The number is 37.

The missing guess can be either 24 or 50 and the missing difference is 8.

Solution:

119

Explanation:
Let the minimum number of chocolates = C
When divided by 2, remainder = 1
When divided by 3, remainder = 2
When divided by 4, remainder = 3
When divided by 5, remainder = 4
When divided by 6, remainder = 5
When divided by 7, remainder = 0

Therefore, C is divisible by 7.

Whenever C is divided by any number less than 7, the remainder is 1 less than the divisor.
This implies that, C + 1 is the LCM of 2, 3, 4, 5 and 6.

Now LCM of 2, 3, 4, 5 and 6 = 60
But 60 - 1 = 59 is not divisible by 7

60 * 2 = 120
120 - 1 = 119 which is divisible by 7

Therefore, C + 1 = 120 or C = 119

Number of minimum number of chocolates in the box = 119

Solution:

She had a 50p coin, a 25p coin and four 10p coins.

Solution:

0(zero) off course.

Solution:

7 years.

Explanation:
Kylian * Thorgan * Eden = 175
and only value that fits in above equation is:
Kylian = Thorgan = 5years
Eden = 7 years