Solution:

24miles/hr (not 25miles/hr which might be guessed by many)

D : distance traveled
T1 : time of going to office
T2 : time of returning back
Y : Average Speed

D = 20 * T1
T1 = D/20

D = 30 * T2
T2 = D/30


2D = Y(T2 + T1)
2D = Y(D/20 + D/30)
2D = Y(3D/60 + 2D/60)
2D = Y(5D/60)
Y = 120D/5D

=> Y = 24

Solution:

takilu had 39 , whisku had 21 and Rumu had 12 liquor initially.


Solve the problem in reverse way as below :
takilu whisku Rumu
24 24 24
12 12 48
6 42 24
39 21 12

Solution:

36 meters.

100/v1 = 80/v2
100/v2 = 80/v3

20+(20/v2)*v3=20+16 = 36

Solution:

58.

As we know LCM of the numbers 3 4 5 & 6 is 60.

So if i divide 60 by any of the four number , it gives remainder as 0.
Now to get reminder as desired, is should be 2 short of 60. (3-1,4-2,5-3,6-4 )

Solution:

20 + 20 + 20

55 + 5

Solution:

11 / .11

Solution:

12

In general, with n+1 people, the number of handshakes is the sum of the first n consecutive numbers: 1+2+3+ ... + n.
Since this sum is n(n+1)/2, we need to solve the equation n(n+1)/2 = 66.
This is the quadratic equation n2+ n -132 = 0. Solving for n, we obtain 11 as the answer and deduce that there were 12 people at the party.

Since 66 is a relatively small number, you can also solve this problem with a hand calculator. Add 1 + 2 = + 3 = +... etc. until the total is 66. The last number that you entered (11) is n.

Solution:

12,345,678,987,654,321

(its amazing and awesome)

Solution:

199 - 99

Solution:

40 balls