Solution:

98

2+3=2*[3+(2-1)]=8
3+7=3*[7+(3-1)]=27
4+5=4*[5+(4-1)]=32
5+8=5*[8+(5-1)]=60
6+7=6*[7+(6-1)]=72
therefore
7+8=7*[8+(7-1)]=98
x+y=x[y+(x-1)]=x^2+xy-x

Solution:

0.1667 or 16.67%

When rolling two fair six-sided dice, there are 36 possible outcomes (6 outcomes for the first die multiplied by 6 outcomes for the second die).

To calculate the probability of rolling a sum of 7, we need to determine the number of combinations that result in a sum of 7. These combinations are:

1 + 6
2 + 5
3 + 4
4 + 3
5 + 2
6 + 1

So, there are 6 favorable outcomes that result in a sum of 7.

The probability of rolling a sum of 7 is calculated by dividing the number of favorable outcomes by the total possible outcomes:

Probability = (Number of Favorable Outcomes) / (Total Possible Outcomes) = 6 / 36 = 1/6 ≈ 0.1667

Therefore, the probability of rolling a sum of 7 with two fair six-sided dice is approximately 0.1667 or 16.67%.

Solution:

Shape A

Shape A features an inner figure(dark black) in the form of a trapezoid.
Conversely, shapes B, C, and D all exhibit an inner figure shaped as a triangle.

As a result, the image that deviates from this pattern is Shape A, making it the odd one out.

Solution:

10

Solution:

4

Solution:

43

Solution:

95

Solution:

24

8 + 8 / 2(1+3)= ?
8 + 8 / 2(4)= ?
8 + 4(4)= ?
8 + 16 = ?
24

Solution:

35

Explanation:
The value of RHS is
(A*A) - (A+A)

i.e
(2*2) - (2+2) = 4 - 4 = 00
(3*3) - (3+3) = 9 - 6 = 03
(4*4) - (4+4) = 16 - 8 = 08
(5*5) - (5+5) = 25 - 10 = 15
(6*6) - (6+6) = 36 - 12 = 24
(7*7) - (7+7) = 49 - 14 = 35

Solution:

82