Solution:

glass + ceiling(Symbol)
= glass ceiling

Solution:

54

Explanation:
7^2 + 2^2 + 1^1
6^2 + 3^2 + 3^2
2^2 + 5^2 + 5^2

Solution:

ground + floor(Symbol)
= ground floor

Solution:

We know that there may be many possibilities and if you find one it is great. For reference we have given one solution below.

(1 + (3 + 4*5)*6)*2

Solution:

Let the speed of red ant be R.
Speed of Black ant be B.
Time at which they cross their paths be T.

Now we will apply the basic formula of distance
Distance = Speed * Time

The Red ant travels R * T distance before meeting and R * 20 after meeting.
The Black ant travels B * T distance before meeting and B * 5 after meeting.

Now as per the question,
The distance traveled by red ant before they both meet will be equal to the distance covered by black ant after they meet. We can say the same for the vice versa case as well.

Thus
R * T = B * 5 and B * T = R * 20

Using both the quations
T = 10

Thus the red ant will require 10 + 20 = 30 seconds to travel the distance.
And the black ant will take 10 + 5 = 15 seconds to travel the distance.

Solution:

Absolute(Maths Symbol) + lee + Not(0)
= Absolutely Not

Solution:

There is only one possible shape i.e. a cone.

Solution:

3 minute and 25 (5/7) seconds.

Explanation:
What you may possibly do is add 3 and 4 minutes and take up the sum of 7 as an average to proceed further. However that is totally wrong as the wind has only supported Josh for 3 minutes while it has acted adversely for 4 minutes.

Thus first we must calculate the distance if he would have travelled for equal time along with wind i.e. 4 minutes. Clearly he would have travelled a mile and 1/3 of a mile in 4 minutes. Now adding the total distance in eight minutes i.e. 2 and 1/3 mile we can get his actual speed and time.

Thus the actual time for a single mile will be 3 minute and 25 (5/7) seconds.

Solution:

For(4) + a + change(delta/change symbol)
= For a change

Solution:

The girl was born on 29 February. Thus her birthday came once in four years only while her sister was born on a normal day and celebrated her birthday every year. Thus the girl had a chance of depositing money only 10 times in 4 years through which she collected $2500 while her sister took $50 from the piggy bank every year making the total amount to be $2000. Thus when the piggy bank was opened, it had just $500.