Solution:

21982030

Explanation:
Next number formed is (number * (number-2)) - number;
i.e
(5 * 3) - 5 => 10
(10 * 8) - 10 => 70
(70 * 68) - 70 => 4690
(4690 * 4688) - 4690 => 21982030

Solution:

13 + 11 + 6 = 30

Explanation
The trick is that you just need to rotate '9' to form '6'.

Solution:

5 => FIVE

Half of five => Remove 2 letters out of 4 i.e Remove letter 'F' AND 'E'.
It remains, 'IV'
The Roman value of 'IV' is 4.

Solution:

13 numbers

Explanation:
Since we are looking to find odd reminder which implies that the remainder will be either 1 or 3
Therefore number must follow below two conditions:
A) We can list number 5n + 1 or 5n + 3. (where n = 0,1,2,3.....)
B) The number must end in 1 or 3.

List of such numbers less than 100 are:
1, 3, 11, 13, 21, 23, 31, 33, 41, 43, 51, 53, 61, 63, 71, 73, 81, 83, 91, 93

Let's remove the nonprime ones which are 1, 21, 33, 51, 63, 81 and 91

So, I will be left with 13 numbers which fit the bill.
3, 11, 13, 23, 31, 41, 43, 53, 61, 71, 73, 83 and 93

Solution:

2003.

Explanation:
Its a series of prime numbes.

Solution:

Pie

Explanation:
This is the bar graph that represents the number (3, 1, 4, 1, 5, 9, 2, 6, 5).
and we know the value of pie is 3.14159265

Solution:

There can be many solutions. Three such solutions are:
A) ((8 - 8)^8)!
B) sqrt(8) * sqrt(8)/8
C) (8*(8 - 8))!

Solution:

5

Explanation
First three equation in the image can be written as :
a) 3 BED = 30
b) 2 BED + BUS = 40
c) BED + 2 BUS+ 2 TROPHY = 60

From equation a)
BED = 10

From equation b)
BUS = 40 -20 =20

From equation c)
10 + 40 + 2 TROPHY = 60

TROPHY = 5

Solution:

The equation can be solved by substituting
B = 7
A = 8
S = 8
E = 3
L = 5

Therefore the equation now looks as:
7483 +
7455
-------
14938
-------

Solution:

3

Explanation:
Fernando + Alonso + McLaren = 6
Fernando x Alonso = 2
Alonso x McLaren = 6

Given.
Fernando x Alonso = 2
Alonso x McLaren = 6

Rewriting Both equations in terms of Alonso,
Fernando = 2/Alonso
McLaren = 6/Alonso

Replacing above values in equation "Fernando + Alonso + McLaren = 6"
2/Alonso + Alonso + 6/Alonso =6
(2 + Alonso^2 + 6)/Alonso = 6
8 + Alonso^2 = 6Alonso
Alonso^2 - 6Alonso + 8 = 0
(Alonso - 4) (Alonso - 2) = 0

Therefore;
Alonso = 4 or 2

Let's take value of Alonso as 2
Fernando = 2/2 = 1
McLaren = 6/2 = 3

Therefore;
McLaren x Fernando = 3 x 1 = 3