Solution:

30%

Explanation:
√9%
=> √9/√100
=> 3/10
=> 30/100
=> 30%

Solution:

J = 1
O = 9
I = 6
N = 8
T = 3
(1+9+6+8+3)*(1+9+6+8+3)*(1+9+6+8+3) = 19683.

Solution:

It is possible when you write the numbers in their Roman form.
XI (11) - When you remove me from XI, it becomes X i.e. 10
IX (9) - When you remove me from IX, it becomes X i.e. 10

Solution:

Your friend's statement is actually true and it's not different from what you have answered.

25 - 55 + (85 + 65) = 25 - 55 + 150 = 120 = 5!
5! (factorial) = 5 * 4 * 3 * 2 * 1 = 120

Yes, that was a tricky question, quite capable to confuse anybody.

Solution:

19(snake) + 1(Echidna) + 80(Bird) Egg =>100 eggs.
Cost:
19*5 + 1 + 4 =>100 pence

Solution:

   9567
+ 1085
======
 10652

Solution:

All Digits [0-9] follow the following pattern: There is one occurrence of all digits in every 10 numbers Example. Digit-9 occurred one time between 10 and 19 in 9, between 20 and 29 in 29
However, for tens(91,92,93...99) and hundreds (900,901.... 999), the occurrence is much more. Since we have included 1000, Therefor 1 is the most occurred digit.
Note: Despite three '0s' in 1000, 0 is not most occurred digit as they don't have tens and hundreds like other digits.

Solution:

The password that opens the chamber is 65292.

Solution:

There can be various solutions. Here are a few that we came up with: 1 + 2 + 4/6 + 5 + 7/3 + 89 = 100
12 + 6/3 + 75 + 8/4 + 9 = 100
1/6 + 2 + 4/8 + 7/3 + 95 = 100
24 + 57 + 6/3 + 8 + 9/1 = 100
36 + 4/8 + 51 + 7/2 + 9 = 100
3/2 + 5 + 6/8 + 7/4 + 91 = 100

Solution:

India has the highest chances of winning the war (47/90)
Missile Firing order:
Chances of Remaining Unhit - Pakistan:
Chances of Remaining Unhit - Srilanka:
Chances of Remaining Unhit - India

Pakistan - Srilanka - India
1/2 0 1/2

Pakistan - India - Srilanka
1/2 0 1/2

India - Pakistan - Srilanka
1/10 16/45 49/90

Srilanka- Pakistan - India
1/2 0 1/2

Srilanka - India - Pakistan
1/10 16/45 49/90

India - Srilanka - Pakistan
1/10 16/45 49/90

Total chances of being unhit (sum of the probabilities divided by 6):
27/90 16/90 47/90