Solution:

Baseball umpire and the Catcher (Eden Hazard was playing baseball.)

Solution:

The code is 645
Explanation :
A) From Clues 1st and 2nd we know that one 9 is not in the code
B) From Clue 2nd we know that 9 3 and 8 are part of code
C) From Clue 3rd we know that 4 and 6 are part of code
D) From Clue 5th we know that 1 and 2 are not part of the code as we know 6 is part of the code and just 1 of 3 numbers is part of code.
E) From Clue 4th we know that 5 is also in the code as 8 and 1 are not part of code.

So the code is: 645

Solution:

They are all anagrams of time-related words.

1. CHARM: MARCH
2. DYNAMO: MONDAY
3. YAM: MAY
4. REAY: YEAR
5. EAR: ERA
6. ONE: EON
7. TOADY: TODAY

Solution:

73

Explanation:
It's a very famous puzzle known as "Josephus Problem Puzzle". It can be solved in various ways but the trick to solve this problem is illustrated below.

Binay number of 100 is: 1100100
complement pf 100 is 0011011, whose decimal equivalent is 27.
The desired answer will be 100 - 27 = 73

Solution:

You just need to check $150 bag.

Explanation:
Note: All bags labels are incorrect.
Case 1: If it contains $100 bill, then
A) Current bag contains $200 bills
B) $100 bag contains $150 bills
C) $200 bag contains $100 bills

Case 2: If it contains $50 bill, then
A) Current bag contains $100 bills.
B) $100 bag contains $200 bills
C) $200 bag contains $150 bills

Solution:

Step1 : Mr.Hinx and Supermodel1, Mr.Hinx back
Step2 : Mr.Hinx and Supermodel2, Mr.Hinx back
Step3 : Blofeld and JamesBond, Blofeld back
Step4 : Mr.Hinx and Secret Diary, Mr.Hinx back
Step5 : Mr.Hinx and Blofeld, Mr.Hinx back
Step6 : Mr.Hinx and secretary1, Mr.Hinx back
Step7 : Mr.Hinx and secretary2

Solution:

The chocolates in the boxes will be as follows:
Box 1 = 1
Box 2 = 2
Box 3 = 4
Box 4 = 8
Box 5 = 16
Box 6 = 32
Box 7 = 64
Box 8 = 128
Box 9 = 256

Here we have taken a geometric progression to facilitate any number of chocolates demanded. In the last box, we will place the number of chocolates left:

Box 10 = 489

If you try now, you will be able to do what is asked.

Solution:

First stack of cards = 11
Second stack of cards = 7
Third stack of cards = 6

First move:
First stack of cards = 11 - 7 = 4
Second stack of cards = 7 + 7 = 14
Third stack of cards = 6

Second move:
First stack of cards = 4
Second stack of cards = 14 - 6 = 8
Third stack of cards = 6 + 6 = 12

Third Move:
First stack of cards = 4 + 4 = 8
Second stack of cards = 8
Third stack of cards = 12 - 4 = 8

Solution:

As you see in the image, we had to move just the circle number 1, 7 and 10 and it is done.

Solution:

63.984375

Explanation:
This question is hypothetical because you cannot transact in fractions in bank account. The following is the solution:

Year Amount Interest and Deduction
Start 63.984375
Y1 End 62.968750 63.984375 * 2 - 65
Y2 End 60.937500 62.96875* 2 - 65
Y3 End 56.875000 60.9375 * 2 - 65
Y4 End 48.750000 56.875 * 2 - 65
Y5 End 32.500000 48.75 * 2 - 65
Y6 End 0.000000 32.5 * 2 - 65 = 0