Ultimate Software Interview Puzzles have been brought to you by GPuzzles.Com. The idea behind this post is to prepare students for the Interview Questions in Ultimate Software.
A Basic info about the company:
Ultimate Software is the manufacturer and provider of cloud-based human capital management (HCM) solutions for businesses. As of December 31, 2012, Ultimate Software reported total revenues of nearly $332.3 million. Headquartered in Weston, FL, Ultimate Software includes more than 1,900 professionals and has more than 2,600 customers of all sizes across myriad industries.
The following Ultimate Software Interview Puzzles/Questions will help you enhance your skills and will offer you better confidence while giving the interview.
In such problems what we generally do or you may say the trick to solve such problems is taking the 3rd root of the number. In this case
6561 = 3^8
Thus one must weigh the stones minimum eight number of times to find out the heavy one.
This can be explained in a better way as well.
Divide 6187 by 3 and we will have three equal groups of 2187 each. Now weigh any two and take the higher quantity and further divide it into 3 parts i.e. 729 each. Once again divide it into three parts and weigh in a similar manner. We will have to keep doing this.
The problem needs to be solved with a simple formula of distance.
Distance = Speed * Time
Suppose that the distance between the home and the office be 30m.
In that case, the speed of the father will be 1m/min
The speed of the son will be 1.5m/min
Now as per the question, the father starts at 10:00am and the son starts at 10:05am
Now at 10:05am
Father travels 5m whereas the son travels 0m
Father travels 10m whereas the son travels 7.5m
Father travels 15m and the son also travels 15m
Thus both of them will meet at a distance of 15m from home i.e. 10:15am.
There is a precious gem whose cost is directly proportional with the cube of its weight. That gem is broken into three pieces whose weights are in the ratio of 4:5:6. If the gem was broken into three pieces of equal weights, then the merchant would have suffered a further loss of 24000.
Can you calculate the cost price of the unbroken fem?
Let V be the value of a precious gem and the weight be W.
Now if we see the condition in the problem
V ∝ W3
V ∝ kW3 ---- (1) [k = constant of variation]
Since the weights of the three broken pieces of the precious gem are proportional to 4: 5: 6, we can fairly that their weights are 4w, 5w and 6w respectively.
Therefore the weight of the unbroken piece of gem = 4w + 5w + 6w = 15w
v = k ((15w)^3)
v = 3375k (w^3) ---- (2)
k (w^3) = v/3375.
Let, v1, v2 and v3 be the values of the 3 pieces of weights 4w, 5w and 6w respectively.
v1 = 64k (w^3)
v2 = 125k (w^3)
v3 = 216k (w^3)
Thus the total value of the 3 pieces of the gem
= v1 + v2 + v3
= 405k (w^3)
From equation 2
The total value of the 3 pieces = 405*v/3375
Loss = v - (405*v/3375) ---- (3)
In a similar fashion
The second time it breaks in three equal parts i.e. 1:1:1
In this case total value equals = 3*v/27 ---- (4)
Thus loss = v-(3*v/27 ---- (5)
Now according to the question,
(5) - (3) = 24000
(8v/9) - (2970v/3375) = 24000
v = 2,700,000
What if we transform the alphabet to their respective number?
RNJ will become 18, 14 and 10 respectively
Now EGI is 5, 7 and 9 respectively
If we take the half of RNJ and reverse the entire order we will get 5, 7 and 9.
Thus we have to apply the same logic with DLT which is 4, 12 and 20 respectively.
Halving it results in 2, 6 and 10 and on reversing it becomes 10, 6 and 2 which can be represented with JFB.
A lady is killed in her apartment. The possible suspect are all her ex - Peter, Jason, Fredd, Danny and Danke. On the crime scene, a calendar is found on which there are certain numbers that are being written with blood - 6, 4, 9, 10 and 11.
The police is not able to find out the killer and then Sherlock is called. Just a look at the numbers and he is able to deduce the killer. Can you?