Solution:

22 times

am
12:00
1:05
2:11
3:16
4:22
5:27
6:33
7:38
8:44
9:49
10:55

pm
12:00
1:05
2:11
3:16
4:22
5:27
6:33
7:38
8:44
9:49
10:55

Solution:

6pm

Explanation:
The time after 24, 000, 000 hours will be the same as it is now. We want the time 3 hours before that and thus you can deduct three hours from 9 pm. So the time will be 6 pm.

Solution:

At 01:05

Solution:

C

VIII has taken place of VII.

Solution:

12:00

both minute and hour clock lie exactly between the number one and two in the number.

Solution:

2 minutes (duration between 9:59 and 10:01)

Solution:

5:19

Starting with the watch on the left, add 42 minutes to the time shown to give the time on the next watch to the right

Solution:

The time at first observation:
1:12

The time at second observation:
3:24

Thus, two hours and twelve minutes have passed between the two observations.

Solution:

In the first observation, the time was 1:12. In the second observation, the time was 3:24.
Therefore, 2 hours and 12 minutes have elapsed.

Solution:

60

Explanation:
You can encode MM in the first digit leaving the bottom segment MM (6^2=64>=60).
You will need some order so that they can represent the MM in binary.
Every single element of the display is a binary digit:
"On"=1
"Off"=0

Now, the seconds can be encoded in the similar fashion by using the second digit.

You can now use the remaining four elements of display (two bottom segments and two dots) to encode HH (4^2=16>=12).