Solution:

There is a simple way that can simplify the problem

Let us just assume that the number of employees are 100
Then the total number of men will be 35% of 100 = 35
Total number of women will be 100 - 35 =65

Now 20% of 35 = 7
And 40% of 65 = 26

Thus the number of employees that went to the trip = 33%

Solution:

In such problems what we generally do or you may say the trick to solve such problems is taking the 3rd root of the number. In this case
6561 = 3^8

Thus one must weigh the stones minimum eight number of times to find out the heavy one.

This can be explained in a better way as well.

Divide 6187 by 3 and we will have three equal groups of 2187 each. Now weigh any two and take the higher quantity and further divide it into 3 parts i.e. 729 each. Once again divide it into three parts and weigh in a similar manner. We will have to keep doing this.

Solution:

The problem needs to be solved with a simple formula of distance.
Distance = Speed * Time
Suppose that the distance between the home and the office be 30m.
In that case, the speed of the father will be 1m/min
The speed of the son will be 1.5m/min

Now as per the question, the father starts at 10:00am and the son starts at 10:05am
Now at 10:05am
Father travels 5m whereas the son travels 0m

At 10:10
Father travels 10m whereas the son travels 7.5m

At 10:15
Father travels 15m and the son also travels 15m

Thus both of them will meet at a distance of 15m from home i.e. 10:15am.

Solution:

Let V be the value of a precious gem and the weight be W.

Now if we see the condition in the problem
V ∝ W3

V ∝ kW3 ---- (1) [k = constant of variation]

Since the weights of the three broken pieces of the precious gem are proportional to 4: 5: 6, we can fairly that their weights are 4w, 5w and 6w respectively.
Therefore the weight of the unbroken piece of gem = 4w + 5w + 6w = 15w

v = k ((15w)^3)
v = 3375k (w^3) ---- (2)
k (w^3) = v/3375.
Let, v1, v2 and v3 be the values of the 3 pieces of weights 4w, 5w and 6w respectively.
v1 = 64k (w^3)
v2 = 125k (w^3)
v3 = 216k (w^3)

Thus the total value of the 3 pieces of the gem
= v1 + v2 + v3
= 405k (w^3)
From equation 2
The total value of the 3 pieces = 405*v/3375
Loss = v - (405*v/3375) ---- (3)

In a similar fashion
The second time it breaks in three equal parts i.e. 1:1:1
In this case total value equals = 3*v/27 ---- (4)
Thus loss = v-(3*v/27 ---- (5)

Now according to the question,
(5) - (3) = 24000
(8v/9) - (2970v/3375) = 24000
v = 2,700,000

Solution:

Before looking at the options find out the relation between Paper and Blackboard. We can write both in Paper and Blackboard.

If we look at the third option i.e. Pencil:Pen, we can write using both of them.

Thus the Pencil:Pen option is the best related with the Original pair.

Solution:

What if we transform the alphabet to their respective number?
RNJ will become 18, 14 and 10 respectively
Now EGI is 5, 7 and 9 respectively
If we take the half of RNJ and reverse the entire order we will get 5, 7 and 9.

Thus we have to apply the same logic with DLT which is 4, 12 and 20 respectively.
Halving it results in 2, 6 and 10 and on reversing it becomes 10, 6 and 2 which can be represented with JFB.

Thus the missing item is JFB.

Solution:

The answer is -113

How?
-3*1 - 1 = -4
-4*2 - 1 = -9
-9*3 - 1 = 28
-28*4 - 1 = -113

Solution:

Let the cost prices of the cell phones be x and 8000 - x

Now the selling price of both of the phones is same
Thus
(140/100)*x = (60/100)*(8000-x)
x = 2400

Thus one of the cell phone has a cost price of 2400 whereas the other phone has the cost price of (8000 - 2400) or 5600.

Solution:

Ponder over the case of multiples of 5

5^5 x 10^10 x 15^15 x 20^20 x 25^25 x 30^30 x 35^35 x 40^40 x 45^45

5^5 x 10^10 x 15^15 x 20^20 x (5^2)^25 x 30^30 x 35^35 x 40^40 x 45^45

5^5 x 10^10 x 15^15 x 20^20 x 5^50 x 30^30 x 35^35 x 40^40 x 45^45

Total zeros at the end of product 5^5 x 10^10 x 15^15 x 20^20 x 25^25 x 30^30 x 35^35 x 40^40 x 45^45 will be 5+10+15+20+50+30+35+40+45 = 250 zeros

Solution:

Jan = 1
Feb = 2
March = 3 and so on

In such manner

6 = June (J)
4 = April (A)
9 = September (S)
10 = October (O)
11 = November (N)

Thus it is Jason who killed the lady.