Solution:

Well that it is quite possible. First we have to take two half-filled barrels and pour them entirely in one of the empty barrels. Then we have to do it once more with another two half-filled barrels. After that, we will have 9 barrels full of wine, three barrels half filled with wine and nine entirely empty barrels.

As we have to divide equally, each son will get 3 barrels full of wine, 3 empty barrels and one half filled barrel.

Solution:

James won; Rhea came in second; Leone came in third.

Solution:

You require to weigh only two times.

Divide the chocolate bars into two groups of three and a group of two. Now weigh the three chocolate bars against the other three. There can be two possibilities

If the scales are even, the heavy one will be between the two left and then you can weigh them against each other and find out which one is heavy.

If the scales are uneven, take the three on the heavy side and pick any two of them for balancing again. If the scales are uneven, you will know which one is heavy and if the scales are even, then the heavier is the one you left.

Solution:

$1.19 is the maximum you can have keeping in mind the condition applied.
The break up will be three quarters, four dimes and four pennies.

Solution:

100.

All the teams but the winning one will lose a game exactly once to satisfy the condition.