There can be myriad ways to create a palindrome. One day, I thought of making my own palindrome. I thought of a number and then decided to add the reversed number to it. Sadly, I did not get a palindrome.
So I kept repeating this step and eventually I succeeded in creating a palindrome. I don't know if you can always create a palindrome using this method but I was able to generate one of four digits.
n a hotel, a man was sleeping when he heard a knock on the door. He shifted the blanket and stepped down from the bed. He waked to the door and opened it to find a stranger standing outside.
Upon opening the gate, that stranger said, "Pardon me, I must have made a mistake. I thought this was my room."
The stranger then walked the corridor and climbed down the stairs. The man closed the door and immediately called the security. He asked them to arrest that stranger immediately.
Why did he asked them to arrest that stranger? What made him suspicious?
Two trains under a controlled experiment begin at a speed of 100 mph in the opposite direction in a tunnel. A supersonic bee is left in the tunnel which can fly at a speed of 1000 mph. The tunnel is 200 miles long. When the trains start running on a constant speed of 100 mph, the supersonic bee starts flying from one train towards the other. As soon as the bee reaches the second train, it starts flying back towards the first train.
If the bee keeps flying to and fro in the tunnel till the trains collide, how much distance will it have covered in total?
A typical way will be to start thinking about summing up the distance that the bee will travel but that will be quite a tedious task. How about we offer you a much easy solution?
The tunnel is 200 miles long and the trains are running at as peed of 100 mph which means that they will collide exactly at the center of the tunnel and seeking their speed, they will collide after an hour.
Now consider the bee which is flying at a speed of 1000 mph and will keep flying till the train collides. As calculated, it will keep flying for an hour which means the distance that it will cover is 1000 miles.
A confectionary shop owner allows children to purchase a chocolate in exchange of five wrappers of the same chocolate. Children from the locality consumed 77 chocolates in a month. Now, they all collected them together and decide to buy back chocolates.
How many chocolates do you think they can buy using those 77 wrappers ?
The children can purchase 19 chocolates in return.
Out of 77 wrappers, 75 will be used to buy 15 chocolates and two will be left spare.
The 15 chocolates will create 15 empty wrappers that can be exchanged to get three chocolates.
Three chocolates will return three wrappers which will help them buy another chocolate.
Now the wrapper from this chocolate and the two spare that were left earlier will get them another chocolate.
15 + 3 + 1 = 19
At a restaurant downtown, Mr. Red, Mr. Blue, and Mr. White meet for lunch. Under their coats they are wearing either a red, blue, or white shirt.Mr. Blue says, 'Hey, did you notice we are all wearing different colored shirts from our names?' The man wearing the white shirt says, 'Wow, Mr. Blue, that's right!'
Can you tell who is wearing what color shirt?
There are 100 doors. 100 strangers have been gathered in the adjacent room. The first one goes and opens every door. The second one goes and shuts down all the even numbered doors – second, fourth, sixth... and so on. The third one goes and reverses the current position of every third door (third, sixth, ninth… and so on.) i.e. if the door is open, he shuts it and if the door is shut, he switches opens it. All the 100 strangers progresses in the similar fashion.
After the last person has done what he wanted, which doors will be left open and which ones will be shut at the end?
Think deeply about the door number 56, people will visit it for every divisor it has. So 56 has 1 & 56, 2 & 28, 4 & 14, 7 & 8. So on pass 1, the 1st person will open the door; pass 2, 2nd one will close it; pass 4, open; pass 7, close; pass 8, open; pass 14, close; pass 28, open; pass 56, close.
Thus we can say that the door will just end up back in its original state for each pair of divisor. But what about the cases in which the pair of divisor has analogous number for example door number 16? 16 has the divisors 1 & 16, 2 & 8, 4&4. But 4 is recurrent because 16 is a perfect square, so you will only visit door number 16, on pass 1, 2, 4, 8 and 16… leaving it open at the end. So only perfect square doors will remain open at the end.
Six identical glasses are in a row.
The first three glasses are filled with juice, and the last three glasses are empty.
By moving only one glass, can you arrange them so that the full and the empty glasses are alternate?