We have arranged matchsticks in a manner that all the first row, second row, first column and third column contain 12 matchsticks each. Can you remove 4 matchsticks and rearrange all the remaining matchsticks that we are still left with 12 matchsticks in the first row, second row, first column and the third column.
One man was moving to and fro in worry when a bright woman noticed him. On asking he told her that while replacing his tire, he incidentally dropped all the four nuts into a deep drain. She told him what to do and he was then able to drive back successfully till his office.
First fill the 8 liters jug complete - 4, 8, 0
Fill the 5 liters jug with 8 liters jug - 4, 3, 5
Pour back the beer from 5 liters jug to 12 liters jug - 9, 3, 0
Pour the 3 liters from 8 liters jug to 5 liters jug - 9, 0, 3
Fill the 8 liters jug completely from 12 liters jug - 1, 8, 3
Fill the 5 liters jug from the 8 liters jug - 1, 6, 5
Pour the entire 5 liters jug back in 12 liters jug - 6, 6, 0
You have successfully split the beer into two equal parts.
A homicide team enters a crime scene where a dead body of a fat old man lies there on the floor with blood oozing out of his head. The victim is holding a gun and a tape recorder lies there by his side. One of the detective picks up the recorder and plays it "I am tired of this life and hence I have decided to relieve myself from the worldly pains". A gunshot follows the message.
The teams starts investigating a murder investigation.
You have ten boxes and an electronic weighing machine. In those ten boxes, you have chocolates. Each chocolate weigh 20 grams. But in one box the chocolates are defective and each weigh 19 grams exactly.
Now you can weigh in the electronic weighing machine but you can use that machine just once. How will you find out which box has the defected chocolates.
If you are thinking to hold one chocolate from each box in hand and then balancing weight in bare hands, you are thinking all wrong.
Let us begin by labelling boxes as 1, 2, 3 and so on till 10.
Now pick one chocolate from box 1, two chocolates from box 2, three from box 3 and so on. In total, you will have 55 chocolates now. (1 + 2 + 3 + ..... + 10)
The ideal weight of the chocolates should be 55 * 20 = 1100. However, somewhere in there are the defected chocolate/s.
You can judge that clearly by noting down the result of 1100 - total weight of chocolates. If the weight is less than 1 gram, the defected box is box 1, if the weight is less than 2 grams, the defected box is box 2 and so on.
I sit on Japan's latest maglev bullet train from its first station. The train starts and is now accelerating and is about to enter the tunnel. What is the best position for me to sit, considering I am a claustrophobic guy?